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6.Permutation and Combination
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A committee of $12$ is to be formed from $9$ women and $8$ men in which at least $5$ women have to be included in a committee. Then the number of committees in which the women are in majority and men are in majority are respectively
A
$4784, 1008$
B
$2702, 3360$
C
$6062, 2702$
D
$2702, 1008$
(IIT-1994)
Solution
(d) The number of ways in which at least $5$ women can be included in a committee is
$^9{C_5}{ \times ^8}{C_7}{ + ^9}{C_6}{ \times ^8}{C_6}{ + ^9}{C_7}{ \times ^8}{C_5}{ + ^9}{C_8}{ \times ^8}{C_4}{ + ^9}{C_9}{ \times ^8}{C_3}$
$ = 1008 + 2352 + 2016 + 630 + 56 = 6062$ ways
(i) The women are in majority in
$(2016 + 630 + 56) = 2702$ cases.
(ii) Men are in majority in $1008$ cases.
Standard 11
Mathematics
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