A conducting sphere of radius $R$ is given a charge $Q.$ The electric potential and the electric field at the centre of the sphere respectively are
$0 $, $\frac{Q}{{4\pi {\varepsilon _0}{R^2}}}$
$\frac{Q}{{4\pi {\varepsilon _0}{R }}}$ ,$0$
$\frac{Q}{{4\pi {\varepsilon _0}{R^{}}}}$ $,\frac{Q}{{4\pi {\varepsilon _0}{R^2}}}$
$0,0$
Considering a group of positive charges, which of the following statements is correct?
Potential difference between centre $\&$ the surface of sphere of radius $R$ and uniform volume charge density $\rho$ within it will be :
Charges are placed on the vertices of a square as shown Let $\vec E$ be the electric field and $V$ the potential at the centre. If the charges on $A$ and $B$ are interchanged with those on $D$ and $C$ respectively, then
Consider a finite insulated, uncharged conductor placed near a finite positively charged conductor. The uncharged body must have a potential
An infinite number of charges each numerically equal to q and of the same sign are placed along the $x-$ axis at $x = 1,2,4,8.... \,metres$. Then the electric potential at $x = 0$ due to this set of charges is