2. Electric Potential and Capacitance
easy

A conducting sphere of radius $R$ is given a charge $Q.$ The electric potential and the electric field at the centre of the sphere respectively are

A

$0 $, $\frac{Q}{{4\pi {\varepsilon _0}{R^2}}}$

B

$\frac{Q}{{4\pi {\varepsilon _0}{R }}}$ ,$0$

C

$\frac{Q}{{4\pi {\varepsilon _0}{R^{}}}}$ $,\frac{Q}{{4\pi {\varepsilon _0}{R^2}}}$

D

$0,0$

(AIPMT-2014)

Solution

For the conducting sphere, 

Potential at the centre $=$ Potential on the sphere

 $ = \frac{1}{{4\pi {\varepsilon _0}}}\frac{Q}{R}$

Electric field at the centre $=0$

Standard 12
Physics

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