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2. Electric Potential and Capacitance
easy
A conducting sphere of radius $R$ is given a charge $Q.$ The electric potential and the electric field at the centre of the sphere respectively are
A
$0 $, $\frac{Q}{{4\pi {\varepsilon _0}{R^2}}}$
B
$\frac{Q}{{4\pi {\varepsilon _0}{R }}}$ ,$0$
C
$\frac{Q}{{4\pi {\varepsilon _0}{R^{}}}}$ $,\frac{Q}{{4\pi {\varepsilon _0}{R^2}}}$
D
$0,0$
(AIPMT-2014)
Solution
For the conducting sphere,
Potential at the centre $=$ Potential on the sphere
$ = \frac{1}{{4\pi {\varepsilon _0}}}\frac{Q}{R}$
Electric field at the centre $=0$
Standard 12
Physics