Gujarati
9-1.Fluid Mechanics
medium

A cubical block of wood $10 \,cm$ on a side floats at the interface between oil and water with its lower surface horizontal and $4\, cm$ below the interface. The density of oil is $0.6gc{m^{ - 3}}$. The mass of block is ...... $gm$

A

$706 $

B

$607$

C

$760$

D

$670$

Solution

(c) Weight of block

= Weight of displaced oil + Weight of displaced water

==> $mg = {V_1}{\rho _0}g + {V_2}{\rho _W}g$

==> $m = (10 \times 10 \times 6) \times 0.6 + (10 \times 10 \times 4) \times 1$ $= 760\, gm.$

Standard 11
Physics

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