14.Probability
easy

एक पासा फेंका जाता है। निम्नलिखित घटनाओं की प्रायिकता ज्ञात कीजिए

$1$ या $1$ से छोटी संख्या प्रकट होना

A

$\frac{1}{6}$

B

$\frac{1}{6}$

C

$\frac{1}{6}$

D

$\frac{1}{6}$

Solution

The sample space of the given experiment is given by 

$S=\{1,2,3,4,5,6\}$

Let $C$ be the event of the occurrence of a number less than or equal to one.

Accordingly, $C\{1\}$

$\therefore P(C)=\frac{\text { Number of outcomes favourable to } C}{\text { Total number of possible outcomes }}=\frac{n(C)}{n(S)}=\frac{1}{6}$

Standard 11
Mathematics

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