A force of ${10^3}$ newton stretches the length of a hanging wire by $1$ millimetre. The force required to stretch a wire of same material and length but having four times the diameter by $1$ millimetre is
A force of ${10^3}$ newton stretches the length of a hanging wire by $1$ millimetre. The force required to stretch a wire of same material and length but having four times the diameter by $1$ millimetre is
- A
$4 \times {10^3}N$
- B
$16 \times {10^3}N$
- C
$\frac{1}{4} \times {10^3}N$
- D
$\frac{1}{{16}} \times {10^3}N$
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