A force of ${10^3}$ newton stretches the length of a hanging wire by $1$ millimetre. The force required to stretch a wire of same material and length but having four times the diameter by $1$ millimetre is

  • A

    $4 \times {10^3}N$

  • B

    $16 \times {10^3}N$

  • C

    $\frac{1}{4} \times {10^3}N$

  • D

    $\frac{1}{{16}} \times {10^3}N$

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