Gujarati
11.Thermodynamics
easy

A gas is suddenly compressed to one fourth of its original volume. What will be its final pressure, if its initial pressure is $P$

A

Lesss than $P$

B

More than $P$

C

$P$

D

Either

Solution

(b) $P{V^\gamma } = $constant ==> $\frac{{{P_2}}}{{{P_1}}} = {\left( {\frac{{{V_1}}}{{{V_2}}}} \right)^\gamma } = {\left( {\frac{{{V_1}}}{{{V_1}/4}}} \right)^\gamma } = {4^\gamma }$
==> ${P_2} = {4^\gamma }P$
As $\gamma$ is always greater than one so ${4^\gamma } > 4$ ==> ${P_2} > 4P$

Standard 11
Physics

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