A geo-stationary satellite is orbiting earth at a height of 6 R above surface of earth, R being radi

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7.Gravitation

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A geo-stationary satellite is orbiting the earth at a height of $6 R$ above the surface of earth, $R$ being the radius of earth. The time period of another satellite at a height of $2.5 R$ from the surface of earth is

A

$10\, hr$

B

$(6/\sqrt 2 )\,hr$

C

$6\, hr$

D

$6\sqrt 2 \,hr$

Solution

(d) Distances of the satellite from the centre are $7R$ and $3.5R$ respectively.

$\frac{{{T_2}}}{{{T_1}}} = {\left( {\frac{{{R_2}}}{{{R_1}}}} \right)^{3/2}}\, $

$\Rightarrow {T_2} = 24\,{\left( {\frac{{3.5R}}{{7R}}} \right)^{3/2}} = 6\sqrt 2 \,hr$

Standard 11

Physics

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