A glass flask is filled up to a mark with 50, cc of mercury at 18°C. If flask and contents are h

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10-1.Thermometry, Thermal Expansion and Calorimetry

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A glass flask is filled up to a mark with $50\, cc$ of mercury at $18°C.$ If the flask and contents are heated to $38°C.$ ......... $cc$ mercury will be above the mark $?$ $(\alpha$ for glass is $ 9 × 10^{-6}{°}C^{-1}$ and coefficient of real expansion of mercury is $180 × 10^{-6}{°}C^{-1})$

A

$0.85$

B

$0.46$

C

$0.15$

D

$0.05$

Solution

(c) Due to volume expansion of both mercury and flask, the change in volume of mercury relative to flask is given by

$\Delta V = {V_0}[{\gamma _L} – {\gamma _g}]\Delta \theta = V[{\gamma _m} – 3{\alpha _g}]\Delta \theta $

$ = 50\,[180 \times {10^{ – 6}} – 3 \times 9 \times {10^{ – 6}}]\,(38 – 18) = 0.153\,cc$

Standard 11

Physics

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