A heavy nucleus at rest breaks into two fragm | vedclass

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Question

(a) By conservation of momentum $m_1v_1 = m_2v_2$ 

==> $\frac{{{v_1}}}{{{v_2}}} = \frac{8}{1} = \frac{{{m_2}}}{{{m_1}}}$&hellip;&hellip; $(

Vedclass · Accepted Answer

$1 : 2      $

Vedclass · Answer

(a) By conservation of momentum $m_1v_1 = m_2v_2$ 

==> $\frac{{{v_1}}}{{{v_2}}} = \frac{8}{1} = \frac{{{m_2}}}{{{m_1}}}$&hellip;&hellip; $(i) $

Also from $r \propto {A^{1/3}}$ 

==> $\frac{{{r_1}}}{{{r_2}}} = {\left( {\frac{{{A_1}}}{{{A_2}}}} \right)^{1/3}} = {\left( {\frac{1}{8}} \right)^{1/3}} = \frac{1}{2}$.

A heavy nucleus at rest breaks into two fragments which fly off with velocities in the ratio $8 : 1$. The ratio of radii of the fragments is

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