4-1.Newton's Laws of Motion
hard

A large number $(n)$ of identical beads, each of mass $m$ and radius $r$ are strung on a thin smooth rigid horizontal rod of length $L\, (L >> r)$ and are at rest at random positions. The rod is mounted between two rigid supports (see figure) . If one of the beads is now given a speed $v$, the average force experienced by each support after a long time is (assume all collisions are elastic)

A$\frac{{m{v^2}}}{{2\left( {L - nr} \right)}}$
B$\frac{{m{v^2}}}{{L - 2nr}}$
C$\frac{{m{v^2}}}{{L - nr}}$
Dzero
(JEE MAIN-2015)

Solution

Space between the supports rm for motion of beads is $L – 2nr$
Average force experinced by each support $F = \frac{{2mv}}{{\frac{{2\left( {L – 2nr} \right)}}{V}}} =\frac{{m{V^2}}}{{L – 2nr}}$
Standard 11
Physics

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