A market research group conducted a survey of $1000$ consumers and reported that $720$ consumers like product $\mathrm{A}$ and $450$ consumers like product $\mathrm{B}$, what is the least number that must have liked both products?
Let $U$ be the set of consumers questioned, $S$ be the set of consumers who liked the product $A$ and $T$ be the set of consumers who like the product $B.$ Given that
$n( U )=1000, n( S )=720, n( T )=450$
So $ n( S \cup T ) =n( S )+n( T )-n( S \cap T ) $
$=720+450-n( S \cap T )=1170-n( S \cap T ) $
Therefore, $n( S \cup T )$ is maximum when $n( S \cap T )$ is least.
But $S \cup T \subset U$ implies $n( S \cup T ) \leq n( U )=1000 .$
So, maximum values of $n( S \cup T )$ is $1000 .$
Thus, the least value of $n( S \cap T )$ is $170 .$
Hence, the least number of consumers who liked both products is $170$
In a certain school, $74 \%$ students like cricket, $76 \%$ students like football and $82 \%$ like tennis. Then, all the three sports are liked by at least $......\%$
An organization awarded $48$ medals in event '$A$',$25$ in event '$B$ ' and $18$ in event ' $C$ '. If these medals went to total $60$ men and only five men got medals in all the three events, then, how many received medals in exactly two of three events?
Two newspaper $A$ and $B$ are published in a city. It is known that $25\%$ of the city populations reads $A$ and $20\%$ reads $B$ while $8\%$ reads both $A$ and $B$. Further, $30\%$ of those who read $A$ but not $B$ look into advertisements and $40\%$ of those who read $B$ but not $A$ also look into advertisements, while $50\%$ of those who read both $A$and $B$ look into advertisements. Then the percentage of the population who look into advertisement is
In a survey of $60$ people, it was found that $25$ people read newspaper $H , 26$ read newspaper $T, 26$ read newspaper $I, 9$ read both $H$ and $I, 11$ read both $H$ and $T,$ $8$ read both $T$ and $1,3$ read all three newspapers. Find:
the number of people who read exactly one newspaper.
In a Mathematics test, the average marks of boys is $x \%$ and the average marks of girls is $y \%$ with $x \neq y$. If the average marks of all students is $z \%$, the ratio of the number of girls to the total number of students is