A market research group conducted a survey of $1000$ consumers and reported that $720$ consumers like product $\mathrm{A}$ and $450$ consumers like product $\mathrm{B}$, what is the least number that must have liked both products?
Let $U$ be the set of consumers questioned, $S$ be the set of consumers who liked the product $A$ and $T$ be the set of consumers who like the product $B.$ Given that
$n( U )=1000, n( S )=720, n( T )=450$
So $ n( S \cup T ) =n( S )+n( T )-n( S \cap T ) $
$=720+450-n( S \cap T )=1170-n( S \cap T ) $
Therefore, $n( S \cup T )$ is maximum when $n( S \cap T )$ is least.
But $S \cup T \subset U$ implies $n( S \cup T ) \leq n( U )=1000 .$
So, maximum values of $n( S \cup T )$ is $1000 .$
Thus, the least value of $n( S \cap T )$ is $170 .$
Hence, the least number of consumers who liked both products is $170$
In a committee, $50$ people speak French, $20$ speak Spanish and $10$ speak both Spanish and French. How many speak at least one of these two languages?
In a group of students, $100$ students know Hindi, $50$ know English and $25$ know both. Each of the students knows either Hindi or English. How many students are there in the group?
Let $\mathrm{U}$ be the set of all triangles in a plane. If $\mathrm{A}$ is the set of all triangles with at least one angle different from $60^{\circ},$ what is $\mathrm{A} ^{\prime} ?$
In a survey of $60$ people, it was found that $25$ people read newspaper $H , 26$ read newspaper $T, 26$ read newspaper $I, 9$ read both $H$ and $I, 11$ read both $H$ and $T,$ $8$ read both $T$ and $1,3$ read all three newspapers. Find:
the number of people who read at least one of the newspapers.
In a town of $10,000$ families it was found that $40\%$ family buy newspaper $A, 20\%$ buy newspaper $B$ and $10\%$ families buy newspaper $C, 5\%$ families buy $A$ and $B, 3\%$ buy $B$ and $C$ and $4\%$ buy $A$ and $C$. If $2\%$ families buy all the three newspapers, then number of families which buy $A$ only is