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13.Oscillations
easy
A mass $m$ is suspended from the two coupled springs connected in series. The force constant for springs are ${K_1}$ and ${K_2}$. The time period of the suspended mass will be
A
$T = 2\pi \sqrt {\left( {\frac{m}{{{K_1} + {K_2}}}} \right)} $
B
$T = 2\pi \sqrt {\left( {\frac{m}{{{K_1} + {K_2}}}} \right)} $
C
$T = 2\pi \sqrt {\left( {\frac{{m({K_1} + {K_2})}}{{{K_1}{K_2}}}} \right)} $
D
$T = 2\pi \sqrt {\left( {\frac{{m{K_1}{K_2}}}{{{K_1} + {K_2}}}} \right)} $
(AIPMT-1990) (AIIMS-2019)
Solution
(c) In series ${k_{eq}} = \frac{{{k_1}{k_2}}}{{{k_1} + {k_2}}}$
so time period $T = 2\pi \sqrt {\frac{{m({k_1} + {k_2})}}{{{k_1}{k_2}}}} $
Standard 11
Physics
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