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એક કણનો પ્રારંભિક વેગ $(2\hat i + 3\hat j$ ) અને પ્રવેગ $(0.3\hat i + 0.2\hat j$ ) છે. તે કણની $ 10 \;s$ પછી ઝડપ કેટલી હશે?
$9$$\sqrt 2 $એકમ
$5$$\sqrt 2 $ એકમ
$5 $ એકમ
$9 $ એકમ
Solution
$\begin{array}{l}
\,\,\,\,\,\,\,\,\,\,\,\,\,Here,\\
Initial\,velocity,\,\overline u = 2\hat i + 3\hat j\\
Acceleration,\,\overline a = 0.3\hat i + 0.2\hat j\\
Time\,,\,t = 10\,s\\
Let\,\overline v \,be\,velocity\,of\,a\,particle\,\\
after\,10\,s.
\end{array}$
$\begin{array}{l}
{\rm{Using,}}\,\overline v \, = \overline u + \,\overline a t\\
\therefore \,\,\,\overline v = \left( {2\hat i + 3\hat j} \right) + \left( {0.3\hat i + 0.2\hat j} \right)\left( {10} \right)\\
\,\,\,\,\,\,\,\,\, = \,2\hat i + 3\hat j + 3\hat i + 2\hat j = 5\hat i + 5\hat j\\
Speed\,of\,the\,particle\,after\,10\,s = \left| {\overline v } \right|\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \sqrt {{{\left( 5 \right)}^2} + {{\left( 5 \right)}^2}} = 5\sqrt 2 \,units
\end{array}$