किसी कण का प्रारंभिक वेग (2 vec{i}+3 vec{j}) | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\begin{array}{l}
\,\,\,\,\,\,\,\,\,\,\,\,\,Here,\
Initial\,velocity,\,\overline u  = 2\hat i + 3\hat j\
Acceleration,\,\overline a  =

Vedclass · Accepted Answer

$5\sqrt 2 $  मात्रक

Vedclass · Answer

$\begin{array}{l}
\,\,\,\,\,\,\,\,\,\,\,\,\,Here,\
Initial\,velocity,\,\overline u  = 2\hat i + 3\hat j\
Acceleration,\,\overline a  = 0.3\hat i + 0.2\hat j\
Time\,,\,t = 10\,s\
Let\,\overline v \,be\,velocity\,of\,a\,particle\,\
after\,10\,s.
\end{array}$

$\begin{array}{l}
{m{Using,}}\,\overline v \, = \overline u  + \,\overline a t\
	herefore \,\,\,\overline v  = \left( {2\hat i + 3\hat j} ight) + \left( {0.3\hat i + 0.2\hat j} ight)\left( {10} ight)\
\,\,\,\,\,\,\,\,\, = \,2\hat i + 3\hat j + 3\hat i + 2\hat j = 5\hat i + 5\hat j\
Speed\,of\,the\,particle\,after\,10\,s = \left| {\overline v } ight|\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = \sqrt {{{\left( 5 ight)}^2} + {{\left( 5 ight)}^2}}  = 5\sqrt 2 \,units
\end{array}$

किसी कण का प्रारंभिक वेग $(2 \vec{i}+3 \vec{j})$ तथा त्वरण $(0.3 \vec{i}+0.2 \vec{j})$ है। $10$ सेकण्ड बाद कण के वेग का मान होगा

Similar Questions