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3-2.Motion in Plane
medium
एक कण इस प्रकार गति करता है कि इसके स्थिति निर्देशांक $(x, y)$ निम्न प्रकार हैं
$(2$मी, $3$मी) समय $t =0$ पर
$(6$मी, $7$मी) समय $t =2$ सेकण्ड पर
$(13$मी, $14$मी$)$ समय $t =5$ सेकेण्ड पर
तो, $t =0$ से $t =5$ सेकण्ड तक, औसत वेग सदिश $\left(\overrightarrow{ V }_{ av }\right)$ होगा
A$\frac{1}{5}\left( {13\hat i + 14\hat j} \right)$
B$\;\frac{7}{3}\left( {\hat i + \hat j} \right)$
C$2\left( {\hat i + \hat j} \right)$
D$\;\frac{{11}}{5}\left( {\hat i + \hat j} \right)$
(AIPMT-2014)
Solution
$\begin{array}{l}
\,\,\,At\,time\,t = 0,\,the\,position\,vector\,of\\
the\,particle\,is\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{{\bar r}_1} = 2\hat i + 3\hat j\\
At\,time\,t = 5\,s,\,the\,position\,vector\,of\\
the\,particle\,is\,\\
\,\,\,\,\,\,\,\,\,\,\,\,\,{{\bar r}_2} = 13\hat i + 14\hat j\\
Displacement\,from\,\,\,{{\bar r}_1}\,to\,\,{{\bar r}_2}\,is
\end{array}$
$\begin{array}{l}
Displacement\,from\,\,\,{{\bar r}_1}\,to\,\,{{\bar r}_2}\,is\\
\Delta \bar r = {{\bar r}_2} – {{\bar r}_1} = \left( {13\hat i + 14\hat j} \right) – \left( {2\hat i + 3\hat j} \right)\\
= 11\hat i + 11\hat j\\
\therefore \,\,\,Average\,velocity,\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{{\bar v}_{av}} = \frac{{\Delta {\bar {r}} }}{{\Delta t}} = \frac{{11\hat i + 11\hat j}}{{5 – 0}} = \frac{{11}}{5}\left( {\hat i + \hat j} \right)
\end{array}$
\,\,\,At\,time\,t = 0,\,the\,position\,vector\,of\\
the\,particle\,is\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{{\bar r}_1} = 2\hat i + 3\hat j\\
At\,time\,t = 5\,s,\,the\,position\,vector\,of\\
the\,particle\,is\,\\
\,\,\,\,\,\,\,\,\,\,\,\,\,{{\bar r}_2} = 13\hat i + 14\hat j\\
Displacement\,from\,\,\,{{\bar r}_1}\,to\,\,{{\bar r}_2}\,is
\end{array}$
$\begin{array}{l}
Displacement\,from\,\,\,{{\bar r}_1}\,to\,\,{{\bar r}_2}\,is\\
\Delta \bar r = {{\bar r}_2} – {{\bar r}_1} = \left( {13\hat i + 14\hat j} \right) – \left( {2\hat i + 3\hat j} \right)\\
= 11\hat i + 11\hat j\\
\therefore \,\,\,Average\,velocity,\\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{{\bar v}_{av}} = \frac{{\Delta {\bar {r}} }}{{\Delta t}} = \frac{{11\hat i + 11\hat j}}{{5 – 0}} = \frac{{11}}{5}\left( {\hat i + \hat j} \right)
\end{array}$
Standard 11
Physics
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