A particle is moving with velocity $\vec v = K(y\hat i + x\hat j)$ where $K$ is a constant. The general equation for its path is
$y^2 = x^2 + $ constant
$y = x^2 + $ constant
$y^2 = x +$ constant
$xy =$ constant
$A$ body $A$ is thrown vertically upwards with such a velocity that it reaches a maximum height of $h$. Simultaneously another body $B$ is dropped from height $h$. It strikes the ground and does not rebound. The velocity of $A$ relative to $B v/s$ time graph is best represented by : (upward direction is positive)
Two stones are thrown up vertically and simultaneously but with different speeds. Which graph correctly represents the time variation of their relative positions $\Delta x$.Assume that stones do not bounce after hitting ground.
What do you mean by term relative velocity ?
A particle is moving in a circular path. The acceleration and momentum of the particle at a certain moment are $\vec a = (4\hat i + 3\hat j)\ m/s^2$ and $\vec p = (8\hat i - 6\hat j)\ kg-m/s$ . The motion of the particle is
A particle moves in space along the path $z = ax^3 + by^2$ in such a way that $\frac{dx}{dt} = c = \frac{dy}{dt}.$ Where $a, b$ and $c$ are contants. The acceleration of the particle is