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7.Gravitation
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A particle of mass $m$ is placed at the centre of a uniform spherical shell of mass $3\,m$ and radius $R$. The gravitational potential on the surface of the shell is
A
$ - \frac{{Gm}}{R}$
B
$ - \frac{{3Gm}}{R}$
C
$ - \frac{{4Gm}}{R}$
D
$ - \frac{{2Gm}}{R}$
Solution
Gravitational potential on the surface of the shell is $\mathrm{V}=$ Gravitational potential due to particle $\left(\mathrm{V}_{1}\right)$
$+$ Gravitational potential due to shell itself $( V_2 )$
$-\frac{\mathrm{Gm}}{\mathrm{R}}+\left(-\frac{\mathrm{G} 3 \mathrm{m}}{\mathrm{R}}\right)=-\frac{4 \mathrm{Gm}}{\mathrm{R}}$
Standard 11
Physics
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