Gujarati
Hindi
7.Gravitation
normal

A particle of mass $m$ is placed at the centre of a uniform spherical shell of mass $3\,m$ and radius $R$. The gravitational potential on the surface of the shell is

A

$ - \frac{{Gm}}{R}$

B

$ - \frac{{3Gm}}{R}$

C

$ - \frac{{4Gm}}{R}$

D

$ - \frac{{2Gm}}{R}$

Solution

Gravitational potential on the surface of the shell is $\mathrm{V}=$ Gravitational potential due to particle $\left(\mathrm{V}_{1}\right)$

$+$ Gravitational potential due to shell itself $( V_2 )$

$-\frac{\mathrm{Gm}}{\mathrm{R}}+\left(-\frac{\mathrm{G} 3 \mathrm{m}}{\mathrm{R}}\right)=-\frac{4 \mathrm{Gm}}{\mathrm{R}}$

Standard 11
Physics

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