The graph between $E$ and $v$ is
(a)Kinetic energy $E = \frac{1}{2}m{v^2}$$⇒$ $E \propto {v^2}$ graph will be parabola symmetric to $E-$axis.
The kinetic energy $K$ of a particle moving along $x$-axis varies with its position $(x)$ as shown in figure The magnitude of force acting on particle at $x=9 \,m$ is ………… $N$
A particle of mass $m_1$ is moving with a velocity $v_1$ and another particle of mass $m_2$ is moving with a velocity $v_2$ . Both of them have the same momentum but their different kinetic energies are $E_1$ and $E_2$ respectively. If $m_1 > m_2$ then
A $120\, g$ mass has a velocity $\vec v = 2\hat i + 5\hat j\,m{s^{ – 1}}$ at a certain instant. Its kinetic energy is ……………… $\mathrm{J}$
A vehicle of mass $m$ is moving on a rough horizontal road with momentum $P$. If the coefficient of friction between the tyres and the road be $\mu$, then the stopping distance is
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