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6.System of Particles and Rotational Motion
medium
A particle of mass $m$ moves in the $XY$ plane with a velocity $v$ along the straight line $AB.$ If the angular momentum of the particle with respect to origin $O$ is $L_A$ when it is at $A$ and $L_B$ when it is at $B,$ then

A
$L_A=L_B$
B
the relationship between $L_A$ and $L_B$ depends upon the slope of the line $AB$
C
$L_A < L_B$
D
$L_A>L_B$
(AIPMT-2007)
Solution

Momentum of momentum is angular momentum. $OP$ is the same whether the mass is at $A$ or $B$.
$\therefore \,{L_A} = {L_B}.$
Standard 11
Physics