A particle of mass $m$ moves in the $XY$ plane with a velocity $v$ along the straight line $AB.$ If the angular momentum of the particle with respect to origin $O$ is $L_A$ when it is at $A$ and $L_B$ when it is at $B,$ then
$L_A=L_B$
the relationship between $L_A$ and $L_B$ depends upon the slope of the line $AB$
$L_A < L_B$
$L_A>L_B$
Why the angular momentum perpendicular to the axis ${L_ \bot }$ in a rotational motion about a fixed axis ?
$A$ uniform rod is fixed to a rotating turntable so that its lower end is on the axis of the turntable and it makes an angle of $20^o$ to the vertical. (The rod is thus rotating with uniform angular velocity about a vertical axis passing through one end.) If the turntable is rotating clockwise as seen from above. What is the direction of the rod's angular momentum vector (calculated about its lower end)?
$A$ time varying force $F = 2t$ is applied on a spool rolling as shown in figure. The angular momentum of the spool at time $t$ about bottommost point is:
The position of a particle is given by : $\overrightarrow {r\,} = (\hat i + 2\hat j - \hat k)$ and momentum $\overrightarrow P = (3\hat i + 4\hat j - 2\hat k)$. The angular momentum is perpendicular to
A metre stick is pivoted about its centre. A piece of wax of mass $20 \,g$ travelling horizontally and perpendicular to it at $5 \,m / s$ strikes and adheres to one end of the stick so that the stick starts to rotate in a horizontal circle. Given the moment of inertia of the stick and wax about the pivot is $0.02 \,kg m ^2$, the initial angular velocity of the stick is ........... $rad / s$