A particle of mass $m$ is moving with constant velocity $v$ parallel to the $x$-axis as shown in the figure. Its angular momentum about origin $O$ is ..........
$m v b$
$mva$
$m v \sqrt{a^2+b^2}$
$m v(a+b)$
A particle starts from the point $(0,8)$ metre and moves with uniform velocity of $\vec{v}=3 \hat{i} \,m / s$. What is the angular momentum of the particle after $5 \,s$ about origin is ........... $kg m ^2 / s$ (mass of particle is $1 \,kg$ )?
A $bob$ of mass $m$ attached to an inextensible string of length $l$ is suspended from a vertical support. The $bob$ rotates in a horizontal circle with an angular speed $\omega\, rad/s$ about the vertical. About the point of suspension
A particle is moving along a straight line with increasing speed. Its angular momentum about a fixed point on this line
Define angular momentum.
A body of mass $5 \mathrm{~kg}$ moving with a uniform speed $3 \sqrt{2} \mathrm{~ms}^{-1}$ in $\mathrm{X}-\mathrm{Y}$ plane along the line $\mathrm{y}=\mathrm{x}+4$.The angular momentum of the particle about the origin will be______________ $\mathrm{kg}\ \mathrm{m} \mathrm{s}^{-1}$.