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14.Probability
easy
A party of $23$ persons take their seats at a round table. The odds against two persons sitting together are
A
$10:1$
B
$1:11$
C
$9:10$
D
None of these
Solution
(a) Required probability $ = \frac{{(21)\,!\,2\,!}}{{(22)\,!}} = \frac{1}{{11}} = \frac{1}{{1 + 10}}$.
Odds against $= 10 : 1$.
Standard 11
Mathematics