Gujarati
14.Probability
easy

A party of $23$ persons take their seats at a round table. The odds against two persons sitting together are

A

$10:1$

B

$1:11$

C

$9:10$

D

None of these

Solution

(a) Required probability $ = \frac{{(21)\,!\,2\,!}}{{(22)\,!}} = \frac{1}{{11}} = \frac{1}{{1 + 10}}$.

Odds against $= 10 : 1$.

Standard 11
Mathematics

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