A physical quantity p is described by the rel | vedclass

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Question

$\begin{array}{l}
Give,\,p = {a^{1/2}}{b^2}{c^3}{d^{ - 4}},\
Maximum\,relative\,error,\
\frac{{\Delta p}}{p} = \frac{1}{2}\frac{{\Delta a}}{a} +

Vedclass · Accepted Answer

$32$

Vedclass · Answer

$\begin{array}{l}
Give,\,p = {a^{1/2}}{b^2}{c^3}{d^{ - 4}},\
Maximum\,relative\,error,\
\frac{{\Delta p}}{p} = \frac{1}{2}\frac{{\Delta a}}{a} + 2\frac{{\Delta b}}{b} + 3\frac{{\Delta c}}{c} + 4\frac{{\Delta d}}{d}\
 = \frac{1}{2} 	imes 2 + 2 	imes 1 + 3 	imes 3 + 4 	imes 5\
 = 32\% 
\end{array}$

A physical quantity $p$ is described by the relation $p\, = a^{1/2}\, b^2\, c^3\, d^{-4}$

If the relative errors in the measurement of $a, b, c$ and $d$ respectively, are $2\% , 1\%, 3\%$ and $5\%$, then the relative error in $P$ will be ........... $\%$

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A physical quantity $p$ is described by the relation $p\, = a^{1/2}\, b^2\, c^3\, d^{-4}$ If the relative errors in the measurement of $a, b, c$ and $d$ respectively, are $2\% , 1\%, 3\%$ and $5\%$, then the relative error in $P$ will be ........... $\%$