A piece of wood from the ruins of an ancient building was found to have a $^{14}C$ activity of $12$ disintegrations per minute per gram of its carbon content. The $^{14}C$ activity of the living wood is $16$ disintegrations per minute per gram. How long ago did the tree, from which the wooden sample came, die? Given half-life of $^{14}C$ is $5760$ years.
According to exponential law,
$\quad \mathrm{I}=\mathrm{I}_{0} e^{-\lambda t}$
$\therefore 12=16 e^{-\lambda t}$
$\therefore \frac{12}{16}=e^{-\lambda t}$
$\therefore e^{\lambda t}=\frac{16}{12}=1.333$
$\therefore \lambda t \ln e=\ln (1.333)$
$\therefore \lambda t(1)=2.303 \log (1.333)$
$\therefore t=\frac{(2.303)(0.1249)\left(\tau_{1 / 2}\right)}{0.693}$
$\therefore t=\frac{(2.303)(0.1249)(5760)}{0.693}$
$\therefore t \approx 2389 \text { years }$
The decay constant for a radioactive nuclide is $1.5 \times 10^{-5} s ^{-1}$. Atomic of the substance is $60\,g$ mole $^{-1},\left( N _{ A }=6 \times 10^{23}\right)$. The activity of $1.0\,\mu g$ of the substance is $.......\,\times 10^{10}\,Bq$
A radioactive isotope has a half-life of $T$ years. How long will it take the activity to reduce to $(a)$ $3.125\% $ $(b)$ $1\% $ of its original value?
Which sample, $A$ or $B$ shown in figure has shorter mean-life?
A sample originally contaived $10^{20}$ radioactive atoms, which emit $\alpha -$ particles. The ratio of $\alpha -$ particles emitted in the third year to that emitted during the second year is $0.3.$ How many $\alpha -$ particles were emitted in the first year?
A radioactive substance emits