A pipe of length 85, cm is closed from one en | vedclass

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Question

For closed organ pipe,

$f=\frac{(2 n+1) v}{4 l}($ where $, n=0,1,1, \ldots)$

According to question,

$\frac{(2 n+1) v}{4 l}<1250$

$2 n+1

Vedclass · Accepted Answer

$6$

Vedclass · Answer

For closed organ pipe,

$f=\frac{(2 n+1) v}{4 l}($ where $, n=0,1,1, \ldots)$

According to question,

$\frac{(2 n+1) v}{4 l}<1250$

$2 n+1 < \frac{1250 	imes 4 l}{v}$

$2 n+1 < \frac{1250 	imes 4 	imes 0.85}{340}$

$\Rightarrow 2 n < 11.5$

$n < 5.75$

So $n=0,1,2,3, \ldots 5$

So, we have $6$ possibilities.

A pipe of length $85\, cm$ is closed from one end. Find the number of possible natural oscillations of air column in the pipe whose frequencies lie below $1250\, Hz$. The velocity of sound in air is $340\, m / s$

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