Gujarati
Hindi
3-2.Motion in Plane
medium

A point moves in $x-y$ plane as per $x=kt,$ $y = kt\left( {1 - \alpha t} \right)$ where $k$ and $\alpha \,$ are $+ve$ constants. The equation of trajectory is 

A$y = x - \frac{{\alpha {x^2}}}{k}$
B$y = x + \frac{{\alpha {x^2}}}{k}$
C$x = y - \frac{{\alpha {y^2}}}{k}$
D$x = y - \frac{{\alpha {y^2}}}{k}$

Solution

$x=\mathbf{K t}$
$t=\frac{x}{k}$
$y=k t-\alpha k t^{2}$
$y=\frac{k x}{k}-\alpha k\left(\frac{x}{k}\right)^{2}$
$y=x-\frac{\alpha x^{2}}{K}$
Standard 11
Physics

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