4.Moving Charges and Magnetism
medium

A proton, a deuteron and an $\alpha-$particle with same kinetic energy enter into a uniform magnetic field at right angle to magnetic field. The ratio of the radii of their respective circular paths is

A

$1: \sqrt{2}: \sqrt{2}$

B

$1: 1: \sqrt{2}$

C

$\sqrt{2}: 1: 1$

D

$1: \sqrt{2}: 1$

(JEE MAIN-2022)

Solution

$R =\frac{\sqrt{2 \,km }}{ qB } \propto \frac{\sqrt{ m }}{ q }$

$\frac{\sqrt{ m }}{ e }: \frac{\sqrt{2 \,m }}{ e }: \frac{\sqrt{4\, m }}{2 e }$

$1: \sqrt{2}: 1$

Standard 12
Physics

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