A radioactive sample is undergoing alpha deca | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Let initial activity be $A _{0}$

$A = A _{0} e ^{-\lambda t_{2}}....(i)$

$\frac{ A }{5}= A _{0} e ^{-\lambda t_{2}}....(ii)$

$( i ) \div ( ii

Vedclass · Accepted Answer

$\frac{ t _{2}- t _{1}}{\ell n 5}$

Vedclass · Answer

Let initial activity be $A _{0}$

$A = A _{0} e ^{-\lambda t_{2}}....(i)$

$\frac{ A }{5}= A _{0} e ^{-\lambda t_{2}}....(ii)$

$( i ) \div ( ii )$

$5= e ^{\lambda\left(t_{2}-t_{1}ight)}$

$\lambda=\frac{\ell n 5}{t_{2}-t_{1}}=\frac{1}{	au}$

$	au=\frac{t_{2}-t_{1}}{\ell n \cdot 5}$

A radioactive sample is undergoing $\alpha$ decay. At any time $t_{1}$, its activity is $A$ and another time $t _{2}$, the activity is $\frac{ A }{5}$. What is the average life time for the sample?

Similar Questions

Calculate the time (in $minutes$) interval between $33 \,\%$ decay and $67\, \%$ decay if half-life of a substance is $20\, minutes.$

$N$ atoms of a radioactive element emit $n$ number of $\alpha$-particles per second. Mean life of the element in seconds, is

In Fig. $X$ represents time and $Y$ represents activity of a radioactive sample. Then the activity of sample, varies with time according to the curve

A radioactive reaction is $_{92}{U^{238}}{ \to _{82}}P{b^{206}}$. How many $\alpha $ and $\beta $ particles are emitted

A radioactive sample of $U^{238}$ decay to $Pb$ through a process for which half life is $4.5 × 10^9$ years. The ratio of number of nuclei of $Pb$ to $U^{238}$ after a time of $1.5 ×10^9$ years (given $2^{1/3} = 1.26$)