A radioactive sample is undergoing $\alpha$ decay. At any time $t_{1}$, its activity is $A$ and another time $t _{2}$, the activity is $\frac{ A }{5}$. What is the average life time for the sample?
$\frac{\ell n 5}{ t _{2}- t _{1}}$
$\frac{ t _{1}- t _{2}}{\ell n 5}$
$\frac{ t _{2}- t _{1}}{\ell n 5}$
$\frac{\ell n \left( t _{2}+ t _{1}\right)}{2}$
An archaeologist analyses the wood in a prehistoric structure and finds that ${C^{14}}$ (Half life $= 5700\, years$) to ${C^{12}} $ is only one- fourth of that found in the cells buried plants. The age of the wood is about ........$years$
Two radioactive materials $X_1$ and $X_2$ contain same number of nuclei. If $6\,\lambda {s^{ - 1}}$ and $4\,\lambda {s^{ - 1}}$ are the decay constants of $X_1$ and $X_2$ respectively the ratio of number of nuclei, undecayed of $X_1$ to that of $X_2$ will be $\left( {\frac{1}{e}} \right)$ after a time
If one starts with one curie of radioactive substance ($T_{1/2} = 12\,hrs$) the activity left after a period of $1$ week will be about
Radioactive element decays to form a stable nuclide, then the rate of decay of reactant is
The half life period of a radioactive element $X$ is same as the mean life time of another radioactive element $Y$. Initially both of them have the same number of atoms. Then