A real value of $x$ will satisfy the equation $\left( {\frac{{3 - 4ix}}{{3 + 4ix}}} \right) = $ $\alpha - i\beta \,(\alpha ,\beta \,{\rm{real),}}$ if
A real value of $x$ will satisfy the equation $\left( {\frac{{3 - 4ix}}{{3 + 4ix}}} \right) = $ $\alpha - i\beta \,(\alpha ,\beta \,{\rm{real),}}$ if
- A
${\alpha ^2} - {\beta ^2} = - 1$
- B
${\alpha ^2} - {\beta ^2} = 1$
- C
${\alpha ^2} + {\beta ^2} = 1$
- D
${\alpha ^2} - {\beta ^2} = 2$
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