A real value of $x$ will satisfy the equation $\left( {\frac{{3 - 4ix}}{{3 + 4ix}}} \right) = $ $\alpha - i\beta \,(\alpha ,\beta \,{\rm{real),}}$ if
${\alpha ^2} - {\beta ^2} = - 1$
${\alpha ^2} - {\beta ^2} = 1$
${\alpha ^2} + {\beta ^2} = 1$
${\alpha ^2} - {\beta ^2} = 2$
The moduli of two complex numbers are less than unity, then the modulus of the sum of these complex numbers
$\left| {\frac{1}{2}({z_1} + {z_2}) + \sqrt {{z_1}{z_2}} } \right| + \left| {\frac{1}{2}({z_1} + {z_2}) - \sqrt {{z_1}{z_2}} } \right|$ =
Let $z$ and $w$ be two complex numbers such that $w=z \bar{z}-2 z+2,\left|\frac{z+i}{z-3 i}\right|=1$ and $\operatorname{Re}(w)$ has minimum value. Then, the minimum value of $n \in N$ for which $w ^{ n }$ is real, is equal to..........
The inequality $|z - 4|\, < \,|\,z - 2|$represents the region given by
Number of complex numbers $z$ such that $\left| z \right| + z - 3\bar z = 0$ is equal to