The solutions of equation in $z$, $| z |^2 -(z + \bar{z}) + i(z - \bar{z})$ + $2$ = $0$ are $(i = \sqrt{-1})$
The solutions of equation in $z$, $| z |^2 -(z + \bar{z}) + i(z - \bar{z})$ + $2$ = $0$ are $(i = \sqrt{-1})$
- A
$2 + i$, $1 -i$
- B
$1 + i$, $1 -i$
- C
$1 + 2i$, $-1 -i$
- D
$1 + i$, $1 + i$
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Let $a = lm\left( {\frac{{1 + {z^2}}}{{2iz}}} \right)$, where $z$ is any non-zero complex number. The set $A = \{ a:\left| z \right| = 1\,and\,z \ne \pm 1\} $ is equal to
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- [JEE MAIN 2013]
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The value of $|z - 5|$if $z = x + iy$, is
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$\frac{1}{1+i}$
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$\frac{1}{1+i}$