8.Mechanical Properties of Solids
medium

A rubber cord $10\, m$ long is suspended vertically. How much does it stretch under its own weight $($Density of rubber is $1500\, kg/m^3, Y = 5×10^8 N/m^2, g = 10 m/s^2$$)$

A

$15×10^{-4} m$

B

$7.5×10^{-4} m$

C

$12×10^{-4} m$

D

$25×10^{-4} m$

Solution

(a) $l = \frac{{{L^2}dg}}{{2Y}} = \frac{{{{(10)}^2} \times 1500 \times 10}}{{2 \times 5 \times {{10}^8}}} = 15 \times {10^{ – 4}}m$

Standard 11
Physics

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