2. Electric Potential and Capacitance
easy

एक समान्तर संधारित्र की प्लेटों के बीच पृथक्कृत नगण्य मोटाई की ऐल्युमीनियम की पत्ती रख दी जाती है। संधारित्र की धारिता

A

बढ़ जायेगी

B

घट जायेगी

C

वही रहेगी

D

अनंत हो जाता है

(AIEEE-2003)

Solution

Capacitance of parellel plate capacitor with a dielectric slab of thickness $t$ inside is given by:

$C =\frac{ A \epsilon_0}{( d – t )+\frac{ t }{ K }}$, where $K$ is the dielectric constant.

When aluminium sheet of negligible thickness is inserted, then thickness of slab $t \rightarrow 0$ and value of $K$ for metal (conductor) will be $\infty$

Therefore $C =\frac{ A \epsilon_0}{ d }$

Hence, capacitance of capacitor will remains unchanged.

Standard 12
Physics

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