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6.System of Particles and Rotational Motion
medium
A solid sphere of mass $500\,g$ and radius $5\,cm$ is rotated about one of its diameter with angular speed of $10\,rad \, s ^{-1}$. If the moment of inertia of the sphere about its tangent is $x \times 10^{-2}$ times its angular momentum about the diameter. Then the value of $x$ will be ..............
A
$34$
B
$35$
C
$36$
D
$38$
(JEE MAIN-2023)
Solution

$I _{ t }= x \times 10^{-2}\,L$
$\frac{7}{5} mR ^2= x \times 10^{-2} \frac{2}{5} mR ^2 \omega$
$\frac{7}{2 \omega}= x \times 10^{-2}=\frac{7}{2 \times 10}$
Standard 11
Physics