10-1.Thermometry, Thermal Expansion and Calorimetry
medium

A steam engine intakes $50\, g$ of steam at $100^{\circ} C$ per minute and cools it down to $20^{\circ} C$. If latent heat of vaporization of steam is $540 \,cal g ^{-1}$, then the heat rejected by the steam engine per minute is .........$\times 10^{3}$$cal.$

A

$91$

B

$71$

C

$31$

D

$39$

(JEE MAIN-2022)

Solution

Heat rejected $= mL _{ f }+ mS \Delta T$

$=(50 \times 540)+50(1)(100-20)$

$=31000 Cal$

$=31 \times 10^{3} Cal$

Standard 11
Physics

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