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10-1.Thermometry, Thermal Expansion and Calorimetry
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A steam engine intakes $50\, g$ of steam at $100^{\circ} C$ per minute and cools it down to $20^{\circ} C$. If latent heat of vaporization of steam is $540 \,cal g ^{-1}$, then the heat rejected by the steam engine per minute is .........$\times 10^{3}$$cal.$
A
$91$
B
$71$
C
$31$
D
$39$
(JEE MAIN-2022)
Solution
Heat rejected $= mL _{ f }+ mS \Delta T$
$=(50 \times 540)+50(1)(100-20)$
$=31000 Cal$
$=31 \times 10^{3} Cal$
Standard 11
Physics
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