Two bodies are projected from ground with same speeds 40 ms ^{-1} at two different angles with respe

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3-2.Motion in Plane

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Two bodies are projected from ground with same speeds $40 ms ^{-1}$ at two different angles with respect to horizontal. The bodies were found to have same range. If one of the body was projected at an angle of $60^{\circ}$, with horizontal then sum of the maximum heights, attained by the two projectiles, is $.......m$. (Given $g =10 ms ^{-2}$ )

A$78$

B$77$

C$80$

D$79$

(JEE MAIN-2023)

Solution

$\Rightarrow \theta_1+\theta_2=90^{\circ}$
$\Rightarrow \theta_2=30^{\circ}$
$\Rightarrow\left(H_{\max }\right)_1+\left(H_{\max }\right)_2$
$=\frac{U^2 \sin ^2 \theta_1}{2 g}+\frac{U^2 \sin ^2 \theta_2}{2 g}$
$=\frac{40^2}{20}\left(\frac{1}{4}+\frac{3}{4}\right)=80 m$

Standard 11

Physics

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(IIT-2022)

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Solution

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