A stone is thrown at an angle $\theta $ to the horizontal reaches a maximum height $H$. Then the time of flight of stone will be
A stone is thrown at an angle $\theta $ to the horizontal reaches a maximum height $H$. Then the time of flight of stone will be
- A
$\sqrt {\frac{{2H}}{g}} $
- B
$2\,\sqrt {\frac{{2H}}{g}} $
- C
$\frac{{2\sqrt {2H\,\sin \theta } }}{g}$
- D
$\frac{{\sqrt {2H\,\sin \theta } }}{g}$
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- [AIPMT 2014]
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