A stone is thrown at an angle theta to the h | vedclass

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Question

(b) $H = \frac{{{u^2}{{\sin }^2}	heta }}{{2g}}$ and $T = \frac{{2u\sin 	heta }}{g}$

$&rArr;$ ${T^2} = \frac{{4{u^2}{{\sin }^2}	heta }}{{{g^2}}}$

Vedclass · Accepted Answer

$2\,\sqrt {\frac{{2H}}{g}} $

Vedclass · Answer

(b) $H = \frac{{{u^2}{{\sin }^2}	heta }}{{2g}}$ and $T = \frac{{2u\sin 	heta }}{g}$

$&rArr;$ ${T^2} = \frac{{4{u^2}{{\sin }^2}	heta }}{{{g^2}}}$

 $\frac{{{T^2}}}{H} = \frac{8}{g}$

$&rArr;$ $T = \sqrt {\frac{{8H}}{g}} = 2\sqrt {\frac{{2H}}{g}} $

A stone is thrown at an angle $\theta $ to the horizontal reaches a maximum height $H$. Then the time of flight of stone will be

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