A trader sells his table at a profit of 15 % | vedclass

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Question

Let the cost price of table be $Rs.$ $t$ and that of chair $Rs$ $c.$

Then $15 \%$ of $t-7 \frac{1}{2} \%$ of $c=50$

i.e. $15 t-7 \frac{1}{2} c=5

Vedclass · Accepted Answer

$\frac{4000}{9}$

Vedclass · Answer

Let the cost price of table be $Rs.$ $t$ and that of chair $Rs$ $c.$

Then $15 \%$ of $t-7 \frac{1}{2} \%$ of $c=50$

i.e. $15 t-7 \frac{1}{2} c=5000$ $...(1)$

$-7 \frac{1}{2} t+15 c=0$ $...(2)$

Solving Eqs. $(1)$ and $(2),$ we get

$c=\frac{Rs. 2000}{9}$ and $t=\frac{Rs. 4000}{9}$

A trader sells his table at a profit of $15 \%$ and the chair at a loss of $7 \frac{1}{2} \%,$ but on the whole he gains $Rs.\, 50 .$ If he sells the table at a loss of $7 \frac{1}{2} \%,$ and chair at a profit of $15 \%,$ then he neither gains nor loses. Find the cost price of the table

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