A vertical electric field of magnitude $4.9 \times 10^{5} N / C$ just prevents a water droplet of a mass $0.1\, g$ from falling. The value of charge on the droplet will be  ........ $\times 10^{-9} \;C$ $\left(\right.$ Given $\left.g =9.8 m / s ^{2}\right)$

  • [JEE MAIN 2022]
  • A

    $1.6 \times 10^{-9} C$

  • B

    $2.0 \times 10^{-9} C$

  • C

    $3.2 \times 10^{-9} C$

  • D

    $0.5 \times 10^{-9} C$

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