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4.Moving Charges and Magnetism
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An electron enters a chamber in which an uniform magnetic field is present as shown in figure. Ignore gravity. During its motion inside the chamber

A
the force on the electron remains constant
B
the kinetic energy of the electron remains constant
C
the momentum of the electron remains constant
D
the speed of the electron increases at a uniform rate
(KVPY-2013)
Solution
(b)
Magnetic force $F$ acting on the electron is perpendicular to $v$ and $B$.
$F =q \cdot( v \times B )$
As $F$ is perpendicular to $v$ so, $F \cdot v =0$.
Hence, work done by force is zero.
As force is not doing any work so magnitude of velocity or kinctic energy of electron remains constant.
Standard 12
Physics
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