An ellipse has eccentricity $\frac{1}{2}$ and one focus at the point $P\left( {\frac{1}{2},\;1} \right)$. Its one directrix is the common tangent nearer to the point $P$, to the circle ${x^2} + {y^2} = 1$ and the hyperbola ${x^2} - {y^2} = 1$. The equation of the ellipse in the standard form, is

  • [IIT 1996]
  • A

    $\frac{{{{(x - 1/3)}^2}}}{{1/9}} + \frac{{{{(y - 1)}^2}}}{{1/12}} = 1$

  • B

    $\frac{{{{(x - 1/3)}^2}}}{{1/9}} + \frac{{{{(y + 1)}^2}}}{{1/12}} = 1$

  • C

    $\frac{{{{(x - 1/3)}^2}}}{{1/9}} - \frac{{{{(y - 1)}^2}}}{{1/12}} = 1$

  • D

    $\frac{{{{(x - 1/3)}^2}}}{{1/9}} - \frac{{{{(y + 1)}^2}}}{{1/12}} = 1$

Similar Questions

What is the equation of the ellipse with foci $( \pm 2,\;0)$ and eccentricity $ = \frac{1}{2}$

The tangent and normal to the ellipse $3x^2 + 5y^2 = 32$ at the point $P(2, 2)$ meet the $x-$ axis at $Q$ and $R,$ respectively. Then the area(in sq. units) of the triangle $PQR$ is

  • [JEE MAIN 2019]

Tangent is drawn to ellipse $\frac{{{x^2}}}{{27}} + {y^2} = 1$ at $(3\sqrt 3 \cos \theta ,\;\sin \theta )$ where $\theta \in (0,\;\pi /2)$. Then the value of $\theta $ such that sum of intercepts on axes made by this tangent is minimum, is

  • [IIT 2003]

If the minimum area of the triangle formed by a tangent to the ellipse $\frac{x^{2}}{b^{2}}+\frac{y^{2}}{4 a^{2}}=1$ and the co-ordinate axis is $kab,$ then $\mathrm{k}$ is equal to ..... .

  • [JEE MAIN 2021]

For $0 < \theta < \frac{\pi}{2}$, four tangents are drawn at the four points $(\pm 3 \cos \theta, \pm 2 \sin \theta)$ to the ellipse $\frac{x^2}{9}+\frac{y^2}{4}=1$. If $A(\theta)$ denotes the area of the quadrilateral formed by these four tangents, the minimum value of $A(\theta)$ is

  • [KVPY 2018]