An ideal monoatomic gas with pressure P, volu | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

For isothermal process:

$P V=P_{t}, 2 V$

$P=2 P_{i}\,\,\,\,\,\,\,\,...(i)$

For adiabatic process $\mathrm{PV}^{\gamma}=\mathrm{P}_{\mathrm{a}

Vedclass · Accepted Answer

$2^{-2/3}$

Vedclass · Answer

For isothermal process:

$P V=P_{t}, 2 V$

$P=2 P_{i}\,\,\,\,\,\,\,\,...(i)$

For adiabatic process $\mathrm{PV}^{\gamma}=\mathrm{P}_{\mathrm{a}}(2 \mathrm{V})^{\gamma}$

$(\because 	ext { for monatomic gas } \gamma=5 / 3)$

or, $\quad 2 \mathrm{P}_{\mathrm{i}} \mathrm{V}^{\frac{5}{3}}=P_{a}(2 \mathrm{V})^{\frac{5}{3}} \quad[	ext { From }(\mathrm{i})]$

$\Rightarrow \frac{P_{a}}{P_{i}}=\frac{2}{2^{\frac{5}{3}}}$

$\Rightarrow \quad \frac{P_{a}}{P_i}=2^{\frac{-2}{3}}$

An ideal monoatomic gas with pressure $P$, volume $V$ and temperature $T$ is expanded isothermally to a volume $2\, V$ and a final pressure $P_i$. If the same gas is expanded adiabatically to a volume $2\,V$, the final pressure is $P_a$ . The ratio $\frac{{{P_a}}}{{{P_i}}}$ is

Similar Questions

Four curves $A, B, C$ and $D$ are drawn in the adjoining figure for a given amount of gas. The curves which represent adiabatic and isothermal changes are

Two gases have the same initial pressure, volume and temperatue. They expand to the same final volume, one adiabatically and the other isothermally

The work done in an adiabatic change in a gas depends only on

During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its temperature. The ratio of $\frac{{{C_P}}}{{{C_V}}}$ for the gas is