Gujarati
11.Dual Nature of Radiation and matter
easy

एक महत्वपूर्ण स्पेक्ट्रमी उत्सर्जन रेखा की तरंगदैध्र्य $21 cm$ है। संगत फोटॉन ऊर्जा होगी

$(h = 6.62 \times {10^{ - 34}}Js;\;\;c = 3 \times {10^8}m/s)$

A

$5.9 \times {10^{ - 4}}eV$

B

$5.9 \times {10^{ - 6}}eV$

C

$5.9 \times {10^{ - 8}}eV$

D

$11.8 \times {10^{ - 6}}eV$

Solution

$E = \frac{{hc}}{\lambda } = \frac{{3 \times {{10}^8} \times 6.62 \times {{10}^{ – 34}}}}{{0.21 \times 1.6 \times {{10}^{ – 19}}}} = 5.9 \times {10^{ – 6}}eV$

Standard 12
Physics

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