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14.Probability
hard
An unbiased coin is tossed. If the outcome is a head then a pair of unbiased dice is rolled and the sum of the numbers obtained on the is noted. If the toss of the coin results in tail then a card from a well-shuffled pack of nine cards numbered $1, 2, 3,….., 9$ is randomly picked and the number on the card is noted. The probability that the noted number is either $7$ or $8$ is
A
$\frac{{13}}{{36}}$
B
$\frac{{15}}{{72}}$
C
$\frac{{19}}{{72}}$
D
$\frac{{19}}{{36}}$
(JEE MAIN-2019)
Solution
$\mathrm{P}(7 \text { or } 8)$
$=P(H) P(7 \text { or } 8)+P(T) P(7 \text { or } 8)$
$=\frac{1}{2} \times \frac{11}{36}+\frac{1}{2} \times \frac{2}{9}=\frac{11}{72}+\frac{1}{9}=\frac{19}{72}$
Standard 11
Mathematics