Check the solutions of the equation $x -2y = 4$ and which are not : $(0,\,2)$

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$(0,\,2)$ means $x=0$ and $y=2$

Putting $x=0$ and $y=2$ in $x-2 y=4,$ we have

                  L.H.S.$= 0-2(2)=-\,4$

But             R.H.S $=4$                  $\therefore $ L.H.S . $\neq $ R.H.S

$\therefore $ $x =0$,  $y =0$ is not a solution.

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