Check the solutions of the equation $x -2y = 4$ and which are not : $(\sqrt{2},\, 4 \sqrt{2})$

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$(\sqrt{2},\, 4 \sqrt{2})$ means $x=\sqrt {2}$ and $y=4\sqrt{2}$

Putting $x=\sqrt {2}$ and $y=4\sqrt {2}$ in $x-2 y=4,$ we get

                  L.H.S.$=\sqrt{2}-2(4 \sqrt{2})=\sqrt{2}-8 \sqrt{2}=\sqrt{2}(1-8)=-7 \sqrt{2}$

But             R . H.S $=4$                  $\therefore $ L.H.S . $\neq $ R.H.S

$\therefore $ $(\sqrt{2},\, 4 \sqrt{2})$ is not a solution.

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