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7.Binomial Theorem
normal
બહુપદી $(x-1) (x-2^1) (x-2^2) .... (x-2^{19})$ માં $x^{19}$ નો સહગુણક મેળવો
A
$2^{20} -\,2^{19}$
B
$-(2^{20} -1)$
C
$2^{20}$
D
એક પણ નહી
Solution
No. of factors is $=20$
Polynomial $=x^{20}-x^{19}\left(1+2+2^{2} \ldots+2^{19}\right)+\ldots \ldots$
Coeff. of $x^{19}=-\left(1+2+2^{2}+\ldots+2^{19}\right)$
$=-\left(\frac{1-2^{20}}{1-2}\right)=-\left(2^{20}-1\right)$
Standard 11
Mathematics