Consider a circle $(x-\alpha)^2+(y-\beta)^2=50$, where $\alpha, \beta>0$. If the circle touches the line $y+x=0$ at the point $P$, whose distance from the origin is $4 \sqrt{2}$ , then $(\alpha+\beta)^2$ is equal to................

  • [JEE MAIN 2024]
  • A

    $103$

  • B

    $102$

  • C

    $55$

  • D

    $100$

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