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Shown in the figure are two point charges $+Q$ and $-Q$ inside the cavity of a spherical shell. The charges are kept near the surface of the cavity on opposite sides of the centre of the shell. If $\sigma _1$ is the surface charge on the inner surface and $Q_1$ net charge on it and $\sigma _2$ the surface charge on the outer surface and $Q_2$ net charge on it then

$\begin{array}{l}
{\sigma _1}\, \ne \,0,\,\,{Q_1}\, = \,0\\
{\sigma _2}\, = \,0,\,\,{Q_2}\, = \,0
\end{array}$
$\begin{array}{l}
{\sigma _1}\, \ne \,0,\,\,{Q_1}\, = \,0\\
{\sigma _2}\, \ne \,0,\,\,{Q_2}\, = \,0
\end{array}$
$\begin{array}{l}
{\sigma _1}\, = \,0,\,\,{Q_1}\, = \,0\\
{\sigma _2}\, = \,0,\,\,{Q_2}\, = \,0
\end{array}$
$\begin{array}{l}
{\sigma _1}\, \ne \,0,\,\,{Q_1}\, \ne \,0\\
{\sigma _2}\, \ne \,0,\,\,{Q_2}\, \ne \,0
\end{array}$
Solution
Inside the cavity net charge is zero.
$\therefore \quad Q_{1}=0$ and $\sigma_{1}=0$
There is no effect of point charges $+Q$
$Q$ and induced charge on inner surface on the outer surface.
$\therefore \quad Q_{2}=0$ and $\sigma_{2}=0$