Consider sets A and B of A={2,4,6,8} and B={6,8,10,12} Find A cap B .

English

Gujarati

Hindi

1.Set Theory

easy

Consider the sets $A$ and $B$ of $A=\{2,4,6,8\}$ and $B=\{6,8,10,12\}$ Find $A \cap B .$

Option A

Option B

Option C

Option D

Solution

We see that $6,8$ are the only elements which are common to both $A$ and $B$. Hence $A \cap B=\{6,8\}$

Standard 11

Mathematics

Share

Similar Questions

Show that for any sets $\mathrm{A}$ and $\mathrm{B}$, $A=(A \cap B) \cup(A-B)$ and $A \cup(B-A)=(A \cup B).$

medium

If $A=\{x \in R:|x|<2\}$ and $B=\{x \in R:|x-2| \geq 3\}$ then

medium

(JEE MAIN-2020)

If $A=\{3,5,7,9,11\}, B=\{7,9,11,13\}, C=\{11,13,15\}$ and $D=\{15,17\} ;$ find

$\left( {A \cap B} \right) \cap \left( {B \cup C} \right)$

easy

If the sets $A$ and $B$ are defined as $A = \{ (x,\,y):y = {e^x},\,x \in R\} $; $B = \{ (x,\,y):y = x,\,x \in R\} ,$ then

easy

If $A$ and $B$ are any two sets, then $A \cup (A \cap B) $ is equal to

easy