Consider the sets $A$ and $B$ of $A=\{2,4,6,8\}$ and $B=\{6,8,10,12\}$ Find $A \cap B .$
Consider the sets $A$ and $B$ of $A=\{2,4,6,8\}$ and $B=\{6,8,10,12\}$ Find $A \cap B .$
We see that $6,8$ are the only elements which are common to both $A$ and $B$. Hence $A \cap B=\{6,8\}$
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