If $A, B$ and $C$ are non-empty sets, then $(A -B) \cup (B -A)$ equals
$(A \cup B) -B$
$A -(A \cap B)$
$(A \cup B) -(A \cap B)$
$(A \cap B) \cup (A \cup B)$
(c) $(A -B) \cup (B -A) = (A \cup B) -(A \cap B).$
If $A, B, C$ be three sets such that $A \cup B = A \cup C$ and $A \cap B = A \cap C$, then
If $A=\{3,6,9,12,15,18,21\}, B=\{4,8,12,16,20\},$ $C=\{2,4,6,8,10,12,14,16\}, D=\{5,10,15,20\} ;$ find
$A-B$
Show that $A \cap B=A \cap C$ need not imply $B = C$
If the sets $A$ and $B$ are defined as $A = \{ (x,\,y):y = {e^x},\,x \in R\} $; $B = \{ (x,\,y):y = x,\,x \in R\} ,$ then
Let $A$ and $B$ be two sets in the universal set. Then $A – B$ equals
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