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13.Nuclei
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સરેરાશ જીવનકાળ પછી વિભંજીત ભાગ કેટલો રહે?
A
$e$
B
$ \frac{1}{e} $
C
$ \frac{{e - 1}}{e} $
D
$ \frac{e}{{e - 1}} $
Solution
(c) By using $N = {N_0}{e^{ – \lambda t}}$ and average life time $t = \frac{1}{\lambda }$
So $N = {N_0}{e^{ – \lambda \times 1/\lambda }} = {N_0}{e^{ – 1}}$
$\Rightarrow \frac{N}{{{N_0}}} = {e^{ – 1}} = \frac{1}{e}$
Now disintegrated fraction $ = 1 – \frac{N}{{{N_0}}} = 1 – \frac{1}{e} = \frac{{e – 1}}{e}$
Standard 12
Physics
